Best answer to AMCAT automata 2015

Mooshak the mouse Maze Question

Problem:

Mooshak the mouse has been placed in a maze.There is a huge chunk of cheese somewhere in the maze. The maze is represented as a two-dimensional array of integers, where 0 represents walls.1 represents paths where mooshak can move and 9 represents the huge chunk of cheese.

Also read: AMCAT Automata Important questions 2015

Mooshak starts in the top left corner at 0.
Write a method is Path of class Maze Path to determine if Mooshak can reach the huge chunk of cheese. The input to is Path consists of a two dimensional array gnd for the maze matrix. the method should return 1 if there is a path from Mooshak to the cheese.and 0 if not Mooshak is not allowed to leave the maze or climb on walls.

EX: 8 by 8(8*8) matrix maze where Mooshak can get the cheese.

1 0 1 1 1 0 0 1
1 0 0 0 1 1 1 1
1 0 0 0 0 0 0 0
1 0 1 0 9 0 1 1
1 1 1 0 1 0 0 1
1 0 1 0 1 1 0 1
1 0 0 0 0 1 0 1
1 1 1 1 1 1 1 1

Test Cases:

Case 1:
Input:[[1,1,1,][9,1,1],[0,1,0]]

Expected return value :1

Explanation:

The piece of cheese is placed at(1,0) on the grid Mooshak can move from (0,0) to (1,0) to reach it or can move from (0,0) to (0,1) to (1,1) to (1,0)

Test case 2:

Input: [[0,0,0],[9,1,1],[0,1,1]]

Expected return value: 0

Explanation:

Mooshak cannot move anywhere as there exists a wall right on (0,0)

Code format: (C Language)

//include header files needed by your program
// some libray functionality may be restricted
// define any function needed
// fucion signature begins, this function is required
Int isPath(int **grid,int m,int n)
{/
/ write your code here
}/
/function signature ends

Java Code format:

//import librays packages needed by your program
// some clases with in a package may be restricted
//define any class and method needed
//class begins ,this class is required
Public class MazePath
{
Public static int isPath(int[][] grid)
// insert your code here
}/
/ method signature ends
}

Java Program Code:

Int isPath(int **grid,int m,int n)
{
Return SolveMazeUtil(grid,0,0,m,n);
}I
nt SolveMazeUtil(int **grid,x,y,m,n)
{
If(x>=0 && x < m && y>=0 && y<n)
{
if(grid[x][y]==9))
{
return 1;
}
// Check if maze[x][y] is valid
if(grid[x][y] == 1)
{
/* Move forward in x direction */
if (solveMazeUtil(grid, x+1, y, m,n) == 1)
return 1;
/* If moving in x direction doesn't give solution then
Move down in y direction */
if (solveMazeUtil(grid, x, y+1, m,n) == 1)
return 1;
/* If none of the above movements work then BACKTRACK:
unmark x,y as part of solution path */
return 0;
}
return 0;
}
return 0;
}

Hello here is a solution of a problem asked in automata AMCAT exam. The solution is in C++ but logic can be applied to any programming language.

Colony of 8 cells arranged in a straight line

Problem: There is a colony of 8 cells arranged in a straight line where each day every cell competes with its adjacent cells(neighbour). Each day, for each cell, if its neighbours are both active or both inactive, the cell becomes inactive the next day, otherwise it becomes active the next day.

Example automata AMCAT fig

#include<iostream>
using namespace std;

int cellCompete(int *cells ,int day){
//write your code here

for (int i=0;i<day;i++){
 
 cells[-1]=0; //assumptions
 cells[8]=0;//assumptions
 int u[8]; //another array to copy value
 for (int i=-1;i<9;i++){
 u[i]=cells[i]; 
 }
 
 for(int j=0;j<8;j++){
 if(u[j-1]==u[j+1]){ //comparing the value of the neighbouring cells of u[]
 cells[j]=0; //changing value of cell according to condition
 }
 else
 cells[j]=1;
 } }
 
for (int i=0;i<8;i++){
cout<<cells[i];
}
return 0;}


int main(){ //main function
int days,cells[]={1,0,0,0,0,1,0,0}; //array to pass through function
int *cellsptr=cells; //creating array values to pointer
cout<<"enter days:"; //for days
cin>>days; 
cout<<"n[1,0,0,0,0,1,0,0]n";
cellCompete(cellsptr, days); //passing to function
return 0;
}